2x^2-132=0

Solution for 2x^2-132=0 equation:

2x^2-132=0

a = 2; b = 0; c = -132;
Δ = b2-4ac
Δ = 02-4·2·(-132)
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{66}}{2*2}=\frac{0-4\sqrt{66}}{4}
=-\frac{4\sqrt{66}}{4}
=-\sqrt{66}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{66}}{2*2}=\frac{0+4\sqrt{66}}{4}
=\frac{4\sqrt{66}}{4}
=\sqrt{66}
$